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0.4x^2+08x=0.2
We move all terms to the left:
0.4x^2+08x-(0.2)=0
We add all the numbers together, and all the variables
0.4x^2+08x-0.2=0
a = 0.4; b = 08; c = -0.2;
Δ = b2-4ac
Δ = 082-4·0.4·(-0.2)
Δ = 64.32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(08)-\sqrt{64.32}}{2*0.4}=\frac{-8-\sqrt{64.32}}{0.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(08)+\sqrt{64.32}}{2*0.4}=\frac{-8+\sqrt{64.32}}{0.8} $
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